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2n^2-17n+27=0
a = 2; b = -17; c = +27;
Δ = b2-4ac
Δ = -172-4·2·27
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{73}}{2*2}=\frac{17-\sqrt{73}}{4} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{73}}{2*2}=\frac{17+\sqrt{73}}{4} $
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